Topic: Optoelectronics
The critical angle $\theta_{c}$ in an optical fiber is given by
Where $n_{1}$ is refractive index of medium 1 and $n_{2}$ is the refractive index of medium 2.
- A. $sin^{-1}(n_{2}/n_{1})$
- B. $sin^{-1}(n_{1}/n_{2})$
- C. $sin^{-1}(n_{2}*n_{1})$
- D. $sin^{-1}n_{2}$
Answer: A. $sin^{-1}(n_{2}/n_{1})$
Explanation: Detailed explanation not provided in the source.