Topic: Communication Systems
The channel capacity under the Gaussian noise environment for a discrete memoryless channel with a bandwidth of 4 MHz and SNR of 31 is
- A. 20 Mbps
- B. 4 Mbps
- C. 8 kbps
- D. 4 kbps
Answer: A. 20 Mbps
Explanation: According to Shannon's channel capacity theorem: $C=B~\log_{2}(1+SNR) = 4\times 10^6 \times \log_{2}(1+31) = 4~\log_{2}32 = 4\times5~\text{Mbps} = 20~\text{Mbps}$.