Topic: Mathematics
The value of x at which y has a minimum for $y=x^{2}-3x+1$ is
- A. $-3/2$
- B. $3/2$
- C. 0
- D. None of these
Answer: B. $3/2$
Explanation: $y=x^{2}-3x+1$. $\frac{dy}{dx}=2x-3=0 \Rightarrow x=\frac{3}{2}$. $\frac{d^{2}y}{dx^{2}}=2>0$. So, at $x=\frac{3}{2}$, y has minimum value.