Topic: Electronics Engineering
An inductor of inductance 0.1 H, carrying current of 6 Amps will store energy of
- A. 6 Joules
- B. 36 Joules
- C. 1.8 Joules
- D. 3.6 Joules
Answer: C. 1.8 Joules
Explanation: $E=\frac{1}{2}LI^{2}=\frac{1}{2}\times0.1\times36 = 1.8$ Joules