ISRO Electronics & Communication (ECE) 2009 - Question 44

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Topic: Electronics Engineering

What is the approximate skin depth in copper at 100 MHz?

  • A. 0.1 micron
  • B. 10 microns
  • C. 10 mm
  • D. 100 mm

Answer: B. 10 microns

Explanation: Skin depth $(\delta)=\frac{1}{\sqrt{\pi f \mu\sigma}}$
Where, Frequency $(f)=100MHz$, Conductivity $(\sigma)=5.8\times10^{7}S$, $\mu=4\pi\times10^{-7}$.
$\delta=\frac{1}{\sqrt{\pi\times100\times10^{6}\times4\pi\times10^{-7}\times5.8\times10^{7}}} = 6.6\times10^{-6}$ as per option approximate answer is (b).

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