Topic: Electronics Engineering
A transfer function $G(s)$ has pole-zero plot as shown in the figure. Given that the steady state function gain is 2, the transfer function $G(s)$ will be given by
- A. $\frac{5(s+1)}{s^{2}+4s+4}$
- B. $\frac{2(s+1)}{s^{2}+4s+5}$
- C. $\frac{10(s+1)}{s^{2}+4s+5}$
- D. $\frac{10(s+1)}{(s+2)^{2}}$
Answer: C. $\frac{10(s+1)}{s^{2}+4s+5}$
Explanation: Zeros at $S=-1$. Poles at $S=-2\pm j$. $Gain(k)=2(dc~gain)$. $G(s)H(s)=\frac{10(s+1)}{s^{2}+4s+5}$