Topic: Communication Systems
An amplifier has an input power of 2 microwatts. The power gain of the amplifier is 60 dB. The output power will be
- A. 6 microwatts
- B. 120 microwatts
- C. 2 milliwatts
- D. 2 watts
Answer: D. 2 watts
Explanation: Power gain (dB) = $10 \log \frac{P_0}{P_{in}}$\n$60=10 \log\frac{P_{0}}{P_{in}}$\n$\frac{P_{0}}{P_{in}}=(10)^{6}$\n$P_{0}=P_{in}\times(10)^{6}=2\times10^{-6}\times10^{6}=2~Watt$