A single-phase, half-bridge inverter has an input voltage of 48 V DC. Inverter is feeding a load of 2.4Ω. The r.m.s. output voltage at fundamental frequency is,
- A. 96/π V
- B. 96/(√2 π) V
- C. 48/π V
- D. 48/(2√2 π) V
Answer: B. 96/(√2 π) V
Explanation: Fundamental RMS output voltage of single-phase half bridge inverter is 2Vs / (√2 π) = 96 / (√2 π) V.