The electric field intensity at a point situated 4 metres from a point charge is 200 N/C. If the distance is reduced to 2 metres, the field intensity will be
- A. 400 N/C
- B. 600 N/C
- C. 800 N/C
- D. 1200 N/C
Answer: C. 800 N/C
Explanation: Electric field intensity E = Q / (4πε0 r²) = 800 N/C at the given distance.