The phasor current through the inductance in the given circuit shown is [Figure description: A current source i = 10 cos 2t (arrow up) in parallel with a 1 H inductor and a 2 Ω resistor.]
- A. 10/√2 at -45°
- B. 10/√2 at 45°
- C. 5 at 45°
- D. 5 at -45°
Answer: A. 10/√2 at -45°
Explanation: Current division between 2 Ω resistor and j2 Ω inductor: IL = 10∠0° × [2 / (2 + j2)] = 10 / (1 + j) = (10/√2)∠-45°.