Two single phase transformers Ta and Tb are connected in parallel to supply a load having impedance per phase of 0.8 + j 0.6 pu at a load terminal voltage of 1∠0° pu. Both transformers Ta and Tb has same impedance of j 0.1pu. on same base. The second transformer Tb is stepped up to a voltage 1.05 times that of Ta. What is the current supplied by Ta and Tb to the load?
- A. Ta = 0.4 - j 0.3 pu and Tb = 0.4 - j 0.3 pu
- B. Ta = 0.4 - j 0.05 pu and Tb = 0.4 - j 0.55 pu
- C. Ta = 0.4 - j 0.55 pu and Tb = 0.4 - j 0.05 pu
- D. Ta = 0.4 - j 0.55 pu and Tb = 0.4 - j0. 35 pu