ISRO Electrical Engineering (EE) 2018 - Question 80

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y = tan^-1(x^2/2) what is dy/dx ?

  • A. 4x/(4 + x)
  • B. 4/(4 + x^2)
  • C. x/(4 + x^2)
  • D. 4x/(4 + x^2)

Answer: D. 4x/(4 + x^2)

Explanation: Excluded from evaluation by ISRO due to typographical errors in option exponents: dy/dx = (x)/(1 + x⁴/4) = 4x / (4 + x⁴).

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