What is the output of XOR gate with A and B as input?
- A. (AB)' + AB, i.e. NOT(AB) + AB
- B. NOT(A + B) · (A + B)
- C. (A + B) · NOT(AB)
- D. NOT(A + B) + AB
Answer: C. (A + B) · NOT(AB)
Explanation: By Boolean algebra: A ⊕ B = A·B' + A'·B = (A + B)·(A' + B') = (A + B) · (AB)' = (A + B) · NOT(AB).