A 3 Phase, 11 kV, 5 MVA alternator has synchronous reactance of 10 Ω per phase. Its excitation is such that the generated emf is 14 kV. If the alternator is connected to infinite bus the maximum output of the alternator at a given excitation is
- A. 15400 kW
- B. 8000 kW
- C. 6200 kW
- D. 5135 kW
Answer: A. 15400 kW
Explanation: Maximum power output Pmax = 3 × (E·V / Xs) = 3 × [(14000/√3) × (11000/√3) / 10] = 14000 × 1100 = 15,400 kW.