Input voltage v = 230 sin(100πt) Volts is given to a converter and the current drawn by the converter is i = 20 sin(100πt - π/3) + 10 sin(300πt + 45°) + 2 sin(700πt - π/6) Amps. What is the active power drawn by the converter?
- A. 2300 W
- B. 1150 W
- C. 4324 W
- D. 2162 W
Answer: B. 1150 W
Explanation: Active power P = V1,rms · I1,rms · cos φ1 = (230/√2) × (20/√2) × cos(60°) = 2300 × 0.5 = 1150 W (higher harmonics contribute zero net active power).