ISRO Electrical Engineering (EE) 2017 - Question 77

All ISRO Electrical Engineering (EE) papers | ISRO Electrical Engineering (EE) 2017

Using trapezoidal rule for the table given below, the integral from 4 to 5.2 of ln x dx will be. [Table: x: 4, 4.2, 4.4, 4.6, 4.8, 5.0, 5.2; Ln x: 1.39, 1.44, 1.48, 1.53, 1.57, 1.61, 1.65]

  • A. 1.8277
  • B. 1.9284
  • C. 1.6424
  • D. 0.98795

Answer: A. 1.8277

Explanation: Trapezoidal rule with step h = 0.2: I ≈ (h/2)·[y0 + yn + 2·Σ y_mid] = 0.1·[1.39 + 1.65 + 2·(1.44 + 1.48 + 1.53 + 1.57 + 1.61)] = 0.1·[3.04 + 15.26] = 0.1 × 18.30 = 1.83 (closest to 1.8277).

| | All questions of ISRO Electrical Engineering (EE) 2017