ISRO Electrical Engineering (EE) 2015 - Question 76

All ISRO Electrical Engineering (EE) papers | ISRO Electrical Engineering (EE) 2015

The square root of 64 ∠36°

  • A. 8 ∠6°
  • B. 8 ∠18°
  • C. 8 ∠36°
  • D. 8 ∠8°

Answer: B. 8 ∠18°

Explanation: Taking the principal square root in polar form: √(64 ∠36°) = √64 ∠(36°/2) = 8 ∠18°.

| | All questions of ISRO Electrical Engineering (EE) 2015