A sinusoidal voltage V = 50 sin wt is applied to a series RL circuit. The current in the circuit is given by I = 25 sin (wt - 53°). The apparent power consumed by the load is
- A. 375 VA
- B. 625 VA
- C. 2500 VA
- D. 750 VA
Answer: B. 625 VA
Explanation: Vrms = 50/√2 V, Irms = 25/√2 A. Apparent power S = Vrms × Irms = (50 × 25) / 2 = 1250 / 2 = 625 VA.