Figure shown below, capacitor C is initially charged to Vo = 50 V with upper plate positive. Switch S is closed at t = 0. Current through the circuit at t = 0 and final voltage across C are respectively [Figure description: A 200 V DC source with its positive terminal at the top connected through a switch S, then a diode D (anode toward the source, voltage VD across it), then a resistor R = 10 Ω, then to a capacitor C (initial voltage Vo = 50 V, upper plate +, voltage Vc across it) that returns to the negative terminal of the 200 V source. A single series loop.]
- A. 15 A, 200 V
- B. 25 A, 250 V
- C. 20 A, 200 V
- D. 15 A, 150 V
Answer: A. 15 A, 200 V
Explanation: i(0) = (200 − 50)/10 = 15 A; the capacitor charges to the source voltage, 200 V.