What is the equivalent capacitance of the following circuit? [Figure description: Capacitors drawn along a single line from left terminal to right terminal: two 10 µF capacitors in series, followed by a parallel combination of a 4 µF capacitor (top branch) and a 6 µF capacitor (bottom branch), followed by a third 10 µF capacitor in series.]
- A. 2.5 µf
- B. 40 µf
- C. 32.4 µf
- D. 4 µf
Answer: A. 2.5 µf
Explanation: 4 µF ∥ 6 µF = 10 µF; four 10 µF in series = 2.5 µF.