The complement of the Boolean expression AB(B'C + AC) is
- A. (A'+B')+(B+C')(A'+C')
- B. (A.B')+(B'C'+A'C')
- C. (A'+B').(B'+C')+(A'+C')
- D. (A+B).(B'+C)(A+C)
Answer: A. (A'+B')+(B+C')(A'+C')
Explanation: The expression simplifies: AB(B'C + AC) = A(BB')C + AABC = 0 + ABC = ABC. The complement is (ABC)' = A' + B' + C'. Option (a) simplifies to this: (A'+B') + (B+C')(A'+C') = A' + B' + A'B + BC + A'C' + CC' = A' + B' + BC + A'C' = A' + B' + C'.