Consider a system where each file is associated with a 16 bit number. For each file, each user should have the read and write capability. How much memory is needed to store each user's access data?
- A. 16 KB
- B. 32 KB
- C. 64 KB
- D. 128 KB
Answer: A. 16 KB
Explanation: 16 bit number => $2^{16} = 65536$ files. \nEach file needs 2 bits (Read, Write). \nTotal bits = $65536 \times 2 = 131072$ bits.\nTotal Bytes = $131072 / 8 = 16384$ bytes = 16 KB.