If the maximum output voltage of a DAC is V volts and if the resolution is R bits then the weight of the most significant bit is
- A. $\frac{V}{2^R - 1}$
- B. $\frac{V(2^{R-1})}{2^R - 1}$
- C. $(2^{R-1}) \cdot V$
- D. $\frac{V}{(2^R - 1)}$
Answer: B. $\frac{V(2^{R-1})}{2^R - 1}$
Explanation: Step size $k = V / (2^R - 1)$.\nMSB weight = $2^{R-1} \times k = V \cdot 2^{R-1} / (2^R - 1)$.