ISRO Computer Science (CSE) 2013 - Question 77

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The binary equivalent of the decimal number 42.75 is

  • A. 101010.110
  • B. 100110.101
  • C. 101010.101
  • D. 100110.110

Answer: A. 101010.110

Explanation: 42 = 32 + 8 + 2 = 101010. 0.75 = 0.11. Result 101010.11.

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