What will be the cipher text produced by the following cipher function for the plain text ISRO with key k = 7. [Consider 'A' = 0, 'B' = 1, ... 'Z' = 25] C_k(M) = (kM + 13) mod 26
- A. RJCH
- B. QIBG
- C. GQPM
- D. XPIN
Answer: A. RJCH
Explanation: I(8)->(56+13)%26=17(R). S(18)->(126+13)%26=9(J). R(17)->(119+13)%26=2(C). O(14)->(98+13)%26=7(H).