What is the maximum number of characters (7 bits + parity) that can be transmitted in a second on a 19.2 Kbps line. This asynchronous transmission requires 1 start bit and 1 stop bit.
- A. 192
- B. 240
- C. 1920
- D. 1966
Answer: C. 1920
Explanation: Total bits per char = 1 (start) + 7 (data) + 1 (parity) + 1 (stop) = 10 bits. Rate = 19200 / 10 = 1920 char/sec.