ISRO Computer Science (CSE) 2013 - Question 13

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The number 1102 in base 3 is equivalent to 123 in which base system?

  • A. 4
  • B. 5
  • C. 6
  • D. 8

Answer: C. 6

Explanation: $1102_3 = 1*27 + 1*9 + 0*3 + 2*1 = 27 + 9 + 2 = 38$. We need $123_x = 38$. $1*x² + 2*x + 3 = 38 \Rightarrow x² + 2x - 35 = 0 \Rightarrow (x+7)(x-5)=0$. Since base > 0, x=5. Wait, is key 5? Options: 4, 5, 6, 8. My calculation x=5. ISRO answer key might be different or I misread the image. Image says "1102 in base 3". $1*3^3 + 1*3^2 + 0*3^1 + 2*3^0 = 27+9+0+2 = 38$. $123_x = x²+2x+3 = 38 \Rightarrow x²+2x-35=0 \Rightarrow x=5$. Option (b) is 5. Let's check ISRO key (b).

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