Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames. How many bits are there in the logical address?
- A. 13 bits
- B. 15 bits
- C. 14 bits
- D. 12 bits
Answer: A. 13 bits
Explanation: 8 pages = 2^3. 1024 words = 2^10. Total logical address bits = 3 + 10 = 13 bits.