ISRO Computer Science (CSE) 2008 - Question 13

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If N² = (7601)_8 where N is a positive integer, then the value of N is

  • A. (241)_5
  • B. (143)_6
  • C. (165)_7
  • D. (39)_16

Answer: B. (143)_6

Explanation: (7601)_8 = 7*8^3 + 6*8^2 + 0*8 + 1 = 3584 + 384 + 1 = 3969. N = $\sqrt{3969}$ = 63. Checking options: (143)_6 = 1*36 + 4*6 + 3 = 36 + 24 + 3 = 63.

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