Section: Engineering Mathematics | Marks: 1
Consider the second order Partial Differential Equation (PDE) 4π₯2 π2π’ ππ₯2 + 4(π₯+ π¦) π2π’ ππ₯ππ¦+ (π₯2 + π¦2) π2π’ ππ¦2 β π’= 0. Then which one of the following statements is correct ?
- A. The PDE is hyperbolic in the region {(π₯, π¦) ββ2: β1 < π₯< 0, π¦< 0}
- B. The PDE is hyperbolic in the region {(π₯, π¦) ββ2: 1 < π₯< β, π¦< 0}
- C. The PDE is elliptic in the region {(π₯, π¦) ββ2: 0 < π₯< 1, π¦> 0}
- D. The PDE is parabolic in the region {(π₯, π¦) ββ2: 1 < π₯< β, π¦< 0}
Answer: A. The PDE is hyperbolic in the region {(π₯, π¦) ββ2: β1 < π₯< 0, π¦< 0}