Section: Engineering Mathematics | Marks: 2
Consider π(π§) = ππ§, where π§= π₯+ ππ¦β‘and π= ββ1. Which of the following statements is correct ?
- A. π is periodic
- B. π is not periodic
- C. |π| = 1
- D. arg(π) = π¦Β± ππβ‘β‘forβ‘allβ‘π= 0, 1, 2, β¦
Answer: A. π is periodic