Section: Engineering Mathematics | Marks: 2
The surface area of the portion of the paraboloid π§= π₯2 + π¦2 that lies between the planes π§= 0 and π§= 1 4 is
- A. π 6 (2β2 β1)
- B. π 2 (2β2 β1)
- C. π(2β2 β1)
- D. π 3 (2β2 β1)
Answer: A. π 6 (2β2 β1)